Pure Math 10 Help!!!!

RF · April 4th, 2003, 00:22

Arg, I have a test on this tomorrow and I have nowhere else to turn to because this stuff is way over my parents head. Anyways.

The subject is Adding and Subtracting Rational Expressions. I know the basics, all I need is someone to do all the steps on 2 questions for me. I know lots of you are math wizes so make me look dumb here

These are the easier questions. The problem with the last question is I dont remember how to get the denominator the same :eyes:. The top one I just have no clue what to do with it

Thanks for any help you can give.

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**Razor Blade** · April 4th, 2003, 00:34

I'm in Applied math 10 so I can't help ya there. Sorry.

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Exodus · April 4th, 2003, 00:40

here you go, for the 2nd one

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**kairi00** · April 4th, 2003, 00:48

Lemme try the first one.

Now to find the lowest common multiple of the 2 things, we need to break them up. Let's try them one at a time.

1. y^2 - 9
You should know that (a^2 - b^2) = (a + b) (a - b). Which means that y^2 - 9 = y^2 - 3^2 = (y + 3) (y - 3)

2. y^2 + 5y + 6
This gives you (y+2)(y+3). I did this one too many times in high school that it's hard for me to explain this; however, notice that 2+3 = 5 and 2*3 = 6. See the pattern?

Now we have (y+3)(y-3) and (y+2)(y+3).

Taking all the unique factors will give you the LCM which is (y-3)(y+2)(y+3).

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RF · April 4th, 2003, 03:49

Thanks guys

EDIT: Ah, thanks kairi00, I get it now. Razor Blade: I did applied math10 last semester cause I didnt know any better and signed up for it in grade 9 with a 75~ avg. The final exam here in Alberta was easy :rofl: I did it in under an hour and got 88%

dont worry, its such a breeze.

edit2: nm exodus. I c now.

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vivrantpig · April 4th, 2003, 08:50

thats algebra 1 isnt it?? i wish i still had algebra... geometry sucks

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**Kurbster** · April 4th, 2003, 12:35

I have to worry about complex imaginary numbers now

It's in my Algebra 2 book, but I'll have to borrow it from someone.

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**Betamax** · April 4th, 2003, 14:04

Complex's aren't too bad once you get used to it. Not too different from real alegbra, except for conjugates, but the basic premise of that isn't too hard to grasp (ie a+iy has a-iy as its conjugate).

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RF · April 4th, 2003, 21:35

I just took my test and I _think_ I did alright. Thanks

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April 4th, 2003, 00:22	#1
RF Canadian Spaceman Join Date: May 2002 Location: Canada Posts: 8,767	Pure Math 10 Help!!!! Arg, I have a test on this tomorrow and I have nowhere else to turn to because this stuff is way over my parents head. Anyways. The subject is Adding and Subtracting Rational Expressions. I know the basics, all I need is someone to do all the steps on 2 questions for me. I know lots of you are math wizes so make me look dumb here These are the easier questions. The problem with the last question is I dont remember how to get the denominator the same :eyes:. The top one I just have no clue what to do with it Thanks for any help you can give. __________________ CPU: Core i7 920 \ MB: EVGA X58 \ RAM: 12GB OCZ DDR3-1600 \ GPU: ATi 5870 HDD: 2x 150GB VelociRaptor R0 / PSU: Enermax Galaxy 850w / OS: Windows 7 x64

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April 4th, 2003, 00:34	#2
Razor Blade Locked and Loaded Join Date: Aug 2002 Location: I AM CANADIAN! Posts: 12,032	I'm in Applied math 10 so I can't help ya there. Sorry. __________________ -------------------------------------------------------------------------------- Core 2 Duo T7300 2.0 GHz ● NVIDIA GeForce 8400GS ● 2GB DDR2 RAM Hitachi 120GB HD ● Dual Layer DVD+/-RW Drive ● Windows Vista Home Premium ● Dell 2007WFP LCD ● Dell XPS M1330 Laptop ● 1TB Western Digital MyBook External HD ● Logitech Z10 Speakers ● PLAYSTATION 3 --------------------------------------------------------------------------------

April 4th, 2003, 00:48	#4
kairi00 Puchiko-nyu! Join Date: Jul 2001 Location: 49° 11' N 123° 10' W Posts: 2,853	Lemme try the first one. Now to find the lowest common multiple of the 2 things, we need to break them up. Let's try them one at a time. 1. y^2 - 9 You should know that (a^2 - b^2) = (a + b) (a - b). Which means that y^2 - 9 = y^2 - 3^2 = (y + 3) (y - 3) 2. y^2 + 5y + 6 This gives you (y+2)(y+3). I did this one too many times in high school that it's hard for me to explain this; however, notice that 2+3 = 5 and 23 = 6. See the pattern? Now we have (y+3)(y-3) and (y+2)(y+3). Taking all the unique factors will give you the LCM which is (y-3)(y+2)(y+3). __________________ "Not every ejaculation deserves a name." --- George Carlin*

April 4th, 2003, 03:49	#5
RF Canadian Spaceman Join Date: May 2002 Location: Canada Posts: 8,767	Thanks guys EDIT: Ah, thanks kairi00, I get it now. Razor Blade: I did applied math10 last semester cause I didnt know any better and signed up for it in grade 9 with a 75~ avg. The final exam here in Alberta was easy :rofl: I did it in under an hour and got 88% dont worry, its such a breeze. edit2: nm exodus. I c now. __________________ CPU: Core i7 920 \ MB: EVGA X58 \ RAM: 12GB OCZ DDR3-1600 \ GPU: ATi 5870 HDD: 2x 150GB VelociRaptor R0 / PSU: Enermax Galaxy 850w / OS: Windows 7 x64

April 4th, 2003, 08:50	#6
vivrantpig (>^_^)> KIRBY Join Date: Sep 2001 Posts: 2,612	thats algebra 1 isnt it?? i wish i still had algebra... geometry sucks __________________ "...we stand strong, even in time of crisis, when our man passed on, we still marched on, Dignified, walkin with our heads up high, Soldiers until the day that we die..." -D.I.T.C "Stand Stong"

April 4th, 2003, 12:35	#7
Kurbster Administrator Join Date: Mar 2002 Location: Massachusetts, USA Posts: 9,440	I have to worry about complex imaginary numbers now It's in my Algebra 2 book, but I'll have to borrow it from someone. __________________

April 4th, 2003, 14:04	#8
Betamax Resident Movie Critic Join Date: Apr 2001 Location: Belfast, Northern Ireland Posts: 9,506	Complex's aren't too bad once you get used to it. Not too different from real alegbra, except for conjugates, but the basic premise of that isn't too hard to grasp (ie a+iy has a-iy as its conjugate). __________________ Superior marketing of an inferior product will always win over inferior marketing of a superior product.

April 4th, 2003, 21:35	#9
RF Canadian Spaceman Join Date: May 2002 Location: Canada Posts: 8,767	I just took my test and I _think_ I did alright. Thanks __________________ CPU: Core i7 920 \ MB: EVGA X58 \ RAM: 12GB OCZ DDR3-1600 \ GPU: ATi 5870 HDD: 2x 150GB VelociRaptor R0 / PSU: Enermax Galaxy 850w / OS: Windows 7 x64